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put this solution on YOUR website!A red ball and green ball are simultaneously tossed into the air. The red ball is given an initial velocity of 96 feet per second, and its height t seconds after it is tossed is -16t^2+p6ft. The green ball is given an initial velocity of 80 feet per second and its height t seconds after it is tossed is -16t^2 + 80 ft
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a. find the polynomial that represents the difference in the heights of the two balls.
Difference = D(t)
D(t) = (-16t^2 + 96t) - (-16t^2 + 80t)
D(t) = -16t^2 + 96t + 16t^2 - 80t
D(t) = 16t
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b. how much higher is the red ball 2 seconds after the ball is tossed?
D(t) = 16(2)
D(t) = 32 ft
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c. in reality when does the difference in the heights stop increasing?
:
After 5 sec, the green ball hits the ground: h(t)= -16(25) + 80(5) = 0
