SOLUTION: if two friends leave from the same place traveling to a destination of 720 miles away, and one leaves 2 hours before the other traveling at a rate of 60 miles an hour and the other
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Question 143652: if two friends leave from the same place traveling to a destination of 720 miles away, and one leaves 2 hours before the other traveling at a rate of 60 miles an hour and the other leaves traveling at a rate of 80 miles an hour, at what time would they pass eachother on the road?
Found 2 solutions by josmiceli, ankor@dixie-net.com:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Imagine you have a stopwatch. Start the stopwatch the instant
the 2nd friend leaves. Then ask: "where is the 1st one at that time?"
He has gone mi
When will they pass eachother?
Call the distance the 1st one has to go
Then the distance the 2nd one has to go will be
The stopwatch will show the same time for both when they meet
for 1st friend
for 2nd friend
-------------------------------------
hrs
They will meet in 6 hours
check:
OK
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
if two friends leave from the same place traveling to a destination of 720 miles away, and one leaves 2 hours before the other traveling at a rate of 60 miles an hour and the other leaves traveling at a rate of 80 miles an hour, at what time would they pass each other on the road?
:
The destination distance is irrelevant, as long as it is greater than the
distance where one passes the other
:
Let t = travel time of the 1st person
then
(t-2) = travel time of the 2nd person
:
We know when 1 passes the other, they will have traveled the same distance
Write a distance equation: Dist speed * time
:
2nd person dist = 1st person dist
80(t-2) = 60t
:
80t - 160 = 60t
;
80t - 60t = +160
:
20t = 160
t =
t = 8 hrs from the time the 1st person starts or 6 hrs after the 2nd person starts:
:
Check by finding the distances:
60*8 = 480
80*6 = 480
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