SOLUTION: Carla can ride her bike 2 mph faster than Karen. It takes Carla 48 minutes less to travel 50 miles than it does Karen. What is Carla's rate (mph)? HELP MUCH APPRECIATED!!!!
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Question 143383This question is from textbook algebra: structure and method: book1
: Carla can ride her bike 2 mph faster than Karen. It takes Carla 48 minutes less to travel 50 miles than it does Karen. What is Carla's rate (mph)? HELP MUCH APPRECIATED!!!!
This question is from textbook algebra: structure and method: book1
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let x=Carla, so x-2=Karen
d=rt __ t=d/r
48 min is 48/60 or 4/5 hr
"It takes Carla 48 minutes less to travel 50 miles than it does Karen"
__ (50/x)+(4/5)=50/(x-2)
multiplying by 5x(x-2) __ 250x-500+4x^2-8x=250x __ subtracting 250x __ 4x^2-8x-500=0
dividing by 4 __ x^2-2x-125=0
use quadratic formula to find x
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