# SOLUTION: At 9 pm, Lucy started to gallop her horse at 20 miles per hour to catch Edmund, who had a three hour head start, and if Lucy was still 30 miles behind at 11 om, how fast was Edmund

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 Question 142815: At 9 pm, Lucy started to gallop her horse at 20 miles per hour to catch Edmund, who had a three hour head start, and if Lucy was still 30 miles behind at 11 om, how fast was Edmund riding?Answer by ptaylor(2048)   (Show Source): You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r Let r=Edmund's rate of speed Before Lucy started, Edmund had already travelled 3r miles. In two hours, Lucy had travelled 20*2 or 40 miles And in the same two hours, Edmund travelled another 2r miles Now we are told that the distance Edmund travelled minus 30 mi equals the distance Lucy travelled, so: 5r-30=40 add 30 to each side 5r=70 divide each side by 5 r=14 mph----------------------------Edmund's rate of speed CK 3*14+2*14-30=40 42+28-30=40 70-30=40 40=40 Hope this helps----ptaylor