SOLUTION: Katy leaves City A for City B at 8 A.M., driving at 52 mi/h. At 10 A.M., Jensen leaves City B for City A, driving at 61 mi/h along the same route. If the cities are 443 mi apart, a

SOLUTION: Katy leaves City A for City B at 8 A.M., driving at 52 mi/h. At 10 A.M., Jensen leaves City B for City A, driving at 61 mi/h along the same route. If the cities are 443 mi apart, a

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Question 135344: Katy leaves City A for City B at 8 A.M., driving at 52 mi/h. At 10 A.M., Jensen leaves City B for City A, driving at 61 mi/h along the same route. If the cities are 443 mi apart, at what time (P.M.) will they meet?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
52X+61(X-2)=443
52X+61X-122=443
113X=443+122
113X=565
X=565/113
X=5 HOURS AFTER KATY LEAVES THEY WILL MEET.
8+5=13 OR 1 PM.
PROOF
52*5+61*3=443
260+183=443
443=443
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