# SOLUTION: I am having problems setting this equation up. The problem is: If two cars leave the same location at the same time, And car one is traveling 20 MPH faster than car two in opposi

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Travel -> SOLUTION: I am having problems setting this equation up. The problem is: If two cars leave the same location at the same time, And car one is traveling 20 MPH faster than car two in opposi      Log On

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 Word Problems: Travel and Distance Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Travel Word Problems Question 1346: I am having problems setting this equation up. The problem is: If two cars leave the same location at the same time, And car one is traveling 20 MPH faster than car two in opposite directions, and they are 168 miles apart 1 1/2 hours later...how fast is each one going? Your help is GREATLY needed. Thank you! Found 2 solutions by khwang, usyim88hk:Answer by khwang(438)   (Show Source): You can put this solution on YOUR website! Assume the speed of car one is x mph, then the speed of car two is x-2 mph. When they travel in the opposite direction, distance = sum of two speed * Time, So, 168 = (x+x-2)* (3/2) = 3x -3, or 3x = 171, x = 57 and x-2 = 55. Answer: speed of car 1 is 57 MPH, speed of car 2 is 55 MPH Answer by usyim88hk(157)   (Show Source): You can put this solution on YOUR website!Let x be the slower car x = slower car x+20 = faster car 168/1.5 = 112 = how much they are apart in one hour x+x+20 = 112 2x = 92 x = 46 So the speed of the slower car is 46mph, the speed of the faster car is 66mph