SOLUTION: An astronaut on the moon throws a baseball upward. The height h of the ball, in feet, x seconds after the ball is thrown is given by the equation.
h+-2.7x^2+30x+6.5
After ho
Algebra.Com
Question 130147: An astronaut on the moon throws a baseball upward. The height h of the ball, in feet, x seconds after the ball is thrown is given by the equation.
h+-2.7x^2+30x+6.5
After how many seconds is the ball 12 feet above the moon's surface?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The height h of the ball, in feet, x seconds after the ball is thrown is given by the equation.
h(t)= -2.7x^2+30x+6.5
After how many seconds is the ball 12 feet above the moon's surface?
-----------
Let the height be 12 and solve for "x".
-2.7x^2 + 30x + 6.5 = 12
-2.7x^2 + 30x - 4.5 = 0
x = [-30 +- sqrt(900 -4*-2.7*-4.5)]/-5.4
x = [-30 +- sqrt(851.4)]/-5.4
x = [-30 +- 29.17876]/-5.4
x = 10.96 seconds and x = 0.1521 seconds
==========================
Cheers,
Stan H.
RELATED QUESTIONS
An astronaut on the moon throws a baseball upward. The astronaut is 6ft, 6 in tall, and... (answered by josmiceli)
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in.... (answered by ikleyn,Alan3354)
An astronaut on the moon throws a baseball upward. The astronaut is 6ft, 6 in. tall and... (answered by josmiceli,ankor@dixie-net.com,nerdybill)
An astronaut on the moon throws a baseball upward. The astronaut is 6 fee, 6 inches tall... (answered by ikleyn)
An astronaut on the moon throws a baseball upward. The height of the ball in feet (y) is... (answered by Boreal)
I am having trouble figuring out how to connect what I know about quadratic equations to... (answered by josgarithmetic)
A baseball player throws a ball upward. The height h of the ball (in feet) t seconds... (answered by fractalier)
The height, h, of a ball on the moon t seconds after it is thrown upward with an initial... (answered by josmiceli)
A baseball is thrown upward with a speed of 128 feet per second. Let h=128-16x^2 model... (answered by josmiceli)