SOLUTION: At 1pm your friend leaves for college traveling on the interstate at a constant speed of 65mph. At 1:24pm you realize he has forgotten some necessary things for living away at coll

Question 126606: At 1pm your friend leaves for college traveling on the interstate at a constant speed of 65mph. At 1:24pm you realize he has forgotten some necessary things for living away at colleg. You drive after your friend maintaining a speed of 70mph. If neither of you alter your speed, how many miles will you travel before you overtake him?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
At 1 pm your friend leaves for college traveling on the interstate at a constant speed of 65 mph. At 1:24 pm you realize he has forgotten some necessary things for living away at college. You drive after your friend maintaining a speed of 70mph. If neither of you alter your speed, how many miles will you travel before you overtake him?
:
Let d = distance traveled when you catch up with your friend
:
Change 24 min to hrs. 24/60 = .4 hrs
:
When this happens, they will have traveled the same distance (d):
;
Write a time equation: Time =
Friends time - .4 hrs = your time
- .4 =
Multiply equation by 65*70 = 4550
4550* - 4550(.4) = 4550*
Cancel out the denominators and you have:
70d - 1820 = 65d
70d - 65d = 1820
5d = 1820
d =
d = 364 miles
:
That seems like a long way. Check solution by finding the travel times
364/65 = 5.6 hr
364/70 = 5.2 hr
---------------
differ = 0.4 hrs; confirms our solution
:
:
Did this make sense? Did I explain it well enough?
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