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Bill and Chris left the student
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Bill and Chris left the student
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Question 125684This question is from textbook Intermediate Algebra Review
: I am having a problem with setting this problem up to solve it.
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Bill and Chris left the student union at the same time on bicycles. Bill traveled east, and Chris traveled west. After 1/2 hour, they were 14 miles apart. If Bill was going 2 miles per hour faster than Chris, how fast was each of the bicycles going? This question is from textbook Intermediate Algebra Review
You can put this solution on YOUR website! Bill and Chris left the student union at the same time on bicycles. Bill traveled east, and Chris traveled west. After 1/2 hour, they were 14 miles apart. If Bill was going 2 miles per hour faster than Chris, how fast was each of the bicycles going?
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Bill DATA:
Rate = x+2 mph ; Time = 1/2 hr ; distance = rt = (x+2)/2 miles
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Chris DATA:
Rate = x mph ; Time = 1/2 hr ; distance = rt = x/2 miles
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EQUATION:
distance + distance = 14 miles
(x+2)/2 + x/2 = 14
(x+2) + x = 28
2x = 26
x = 13 mph ( Chris rate)
x+2= 15 mph ( Bill Rate)
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Cheers,
Stan H.
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