SOLUTION: I am having a problem with setting this problem up to solve it. _______________________________________________________________________________ Bill and Chris left the student

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Question 125684This question is from textbook Intermediate Algebra Review
: I am having a problem with setting this problem up to solve it.
_______________________________________________________________________________
Bill and Chris left the student union at the same time on bicycles. Bill traveled east, and Chris traveled west. After 1/2 hour, they were 14 miles apart. If Bill was going 2 miles per hour faster than Chris, how fast was each of the bicycles going?This question is from textbook Intermediate Algebra Review

Answer by stanbon(48558) About Me  (Show Source):
You can put this solution on YOUR website!
Bill and Chris left the student union at the same time on bicycles. Bill traveled east, and Chris traveled west. After 1/2 hour, they were 14 miles apart. If Bill was going 2 miles per hour faster than Chris, how fast was each of the bicycles going?
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Bill DATA:
Rate = x+2 mph ; Time = 1/2 hr ; distance = rt = (x+2)/2 miles
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Chris DATA:
Rate = x mph ; Time = 1/2 hr ; distance = rt = x/2 miles
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EQUATION:
distance + distance = 14 miles
(x+2)/2 + x/2 = 14
(x+2) + x = 28
2x = 26
x = 13 mph ( Chris rate)
x+2= 15 mph ( Bill Rate)
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Cheers,
Stan H.