SOLUTION: MARY LEFT ATLANTA WITH A SPEED OF 45MPH. FRED ALSO LEFT AT THE SAME TIME IN THE OPPOSITE DIRECTION AT A SPEED OF 60MPH. FIND HOW MANY HOURS FRED MUST TRAVEL BEFORE THEY ARE 318 MIL

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Question 1203882: MARY LEFT ATLANTA WITH A SPEED OF 45MPH. FRED ALSO LEFT AT THE SAME TIME IN THE OPPOSITE DIRECTION AT A SPEED OF 60MPH. FIND HOW MANY HOURS FRED MUST TRAVEL BEFORE THEY ARE 318 MILES APART
Found 3 solutions by ikleyn, math_tutor2020, josgarithmetic:
Answer by ikleyn(52754)   (Show Source): You can put this solution on YOUR website!
.

They separate with the rate of 45 mph + 60 mph = 105 mph.


To find the answer, you should divide 318 miles by 105 mph.

------------------

My interior voice tells me that correct number in the problem
should be 315 miles, instead of yours 318 miles.



Answer by math_tutor2020(3816)   (Show Source): You can put this solution on YOUR website!

Question: Mary left Atlanta with a speed of 45mph. Fred also left at the same time in the opposite direction at a speed of 60mph. Find how many hours Fred must travel before they are 318 miles apart

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x = number of hours

Mary:
distance = rate*time
d = 45x

Fred
d = 60x

Distance between Mary and Fred = 45x+60x = 105x

We want that distance to be 318 miles
105x = 318
x = 318/105
x = 3.02857 hours approximately
Answer by josgarithmetic(39613)   (Show Source): You can put this solution on YOUR website!
Both Mary and Fred left from Atlanta? If this the case then they are separating at rate of 45+60=105 miles per hour.

THEY ARE 318 miles apart after some x time in hours:
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