SOLUTION: A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph. One and one-half hours later, his support staff leaves the base in a car going 40 mph in the

Question 1202697: A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph. One and one-half hours later, his support staff leaves the base in a car going 40 mph in the same direction. How long will it take the support staff to catch up with the cyclist?
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52866)   (Show Source): You can put this solution on YOUR website!
.
A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph.
One and one-half hours later, his support staff leaves the base in a car going 40 mph
in the same direction. How long will it take the support staff to catch up with the cyclist?
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Let t be the time for the support staff to catch up the cyclist So, x is the unknown value under the problems question. Thus the support staff moves during t hours; the cyclist moves during (t+1.5) hours. The travel distance is the same for both of them So, we write the distance equation 40*t = 16(t+1.5). The equation is ready. To solve it, simplify step by step 40t = 16t + 24 40t - 16t = 24 24t = 24 t = 24/24 = 1 hour. ANSWER. The support staff will catch up with the cyclist in 1 hour.

Solved.

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Answer by josgarithmetic(39628)   (Show Source): You can put this solution on YOUR website!
Cyclist traveled miles when support staff began to travel.

Rate of approach, miles per hour

Time x, for support staff to catch up?

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