SOLUTION: Two cars are travelling in opposite directions at different rates.two hours later ,the cars are 110 mi apart.express the distance travelled by the slower car

Question 1201875: Two cars are travelling in opposite directions at different rates.two hours later ,the cars are 110 mi apart.express the distance travelled by the slower car
Found 4 solutions by ikleyn, greenestamps, math_tutor2020, josgarithmetic:
Answer by ikleyn(52858)   (Show Source): You can put this solution on YOUR website!
.

Impossible to answer, since the input information, presented in the post, is not enough.

In short, the "problem" is DEFECTIVE.

//////////////////

With the problems, presented and formulated as this one in this post,
you may feel free to throw them away to the closest garbage bin.

They are not applicable for any other purpose and for any other use.

Keep the Internet clean ( ! )

Answer by greenestamps(13203)   (Show Source): You can put this solution on YOUR website!

Insufficient information; and poor wording....

"different rates" -- the problem can't be answered without knowing the difference between the rates.

"two hours later..." -- later than what?

How far apart are the two cars at the beginning of those two hours? The statement of the problem doesn't say they start at the same place.

Correct the statement of the problem and re-post....

Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

x = slower speed
x+k = faster speed
where k is some positive real number, k > 0

= distance traveled by the slower car
= distance traveled by the faster car

Slower car:
distance = rate*time
d = r*t
= x*2
= 2x

Faster car:
d = r*t
= (x+k)*2
= 2x+2k
= +2k

Their individual travel distances add together to get the total distance between them, because the cars travel in opposite directions.
Draw out a number line to see why this is the case.
I'll assume the cars start off at the same location.
+ = 110
2x+2x+2k = 110
4x+2k = 110
2(2x+k) = 110
2x+k = 110/2
2x+k = 55
2x = 55-k
= 55-k
If we knew the value of k, then we can find the distance the slower car traveled.

To avoid being zero or negative, we must have 55-k > 0 which leads to k < 55

Earlier it was mentioned that k > 0
So 0 < k < 55

Answer by josgarithmetic(39626)   (Show Source): You can put this solution on YOUR website!
If opposite directions East and West, then let speeds of each be e and w.
110 miles apart after 2 hours travel time.
You were not given which is the slower or faster car. Only that they go in
opposite directions, and if assuming they begin at same time and from same
starting point then

SPEED TIME DISTANCE EAST e 2 (e)(2) WEST w 2 (w)(2) TOTAL same 2 110

This is about as much as can be done.
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