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Working together, two men can do a particular job in 20 days. 
Working alone however, it would take one man 9 days longer than the other to complete the job. 
How long would it take each man to do the job separately?
~~~~~~~~~~~~~~~~~
Let x be the number of day for the faster man to do the job alone.
Then the other man can complete the job in (x+9) days.
In one day, 1st man can do    of the entire job.
In one day, 2nd man can do    of the entire job.
Working together, they can do   +   of the entire job per day.
According to the condition, this part,  + ,  is    of the job.
So you get your basic equation
     +  = .    (1)
    +--------------------------------------------------+
    |      At this point, the setup is complete,       |
    |   and now your task is to solve this equation.   |
    +--------------------------------------------------+
For it, multiply both sides of equation (1) by 20x*(x+9) and simplify step by step.
    20(x+9) + 20x = x*(x+9)
    20x + 180 + 20x = x^2 + 9x
     x^2 - 31x - 180 = 0.
Factor left side
    (x+5)*(x-36) = 0
Of two roots,  -5 and 36, only positive root is the solution.
Thus 1st man can complete the job in 36 days;  2nd man can complete the job in 36+9 = 45 days, 
working alone.
CHECK.  We check equation (1)
         +  =  =  =  =  = .
        ! CORRECT !
Solved.
It is a typical example on how to solve similar problems.