SOLUTION: A car drives 500 ft on a road that is inclined 12° to the horizontal. The car weighs 2500 lb. Thus gravity acts straight down on the car with a constant force F = -2500j. Find th
Algebra.Com
Question 1198125: A car drives 500 ft on a road that is inclined 12° to the horizontal. The car weighs 2500 lb. Thus gravity acts straight down on the car with a constant force F = -2500j. Find the work done by
the car in overcoming gravity.
Answer by ikleyn(52786) (Show Source): You can put this solution on YOUR website!
.
Due to the Conservation Law of mechanical energy, the work done by the car engine
is equal to the change of the potential energy of the car.
The change of the potential energy of the car is
2500*500*sin(12°) = 2500*500*0.2079 = 259875 lb*ft, approximately. ANSWER
Solved, answered and explained.
RELATED QUESTIONS
A man drives 500 ft along a road which is inclined 20° to the horizontal. How high above... (answered by nerdybill)
a man drives 500 miles along an inclined road of 20 degrees to horizontal. How high above (answered by solver91311)
Monica just got a new car and she wants to ride it to the top of a mountain and visit a... (answered by ikleyn)
A road has a steady gradient of 1 in 10.
A car starts from the bottom of the inclined... (answered by addingup)
please help
Topic : vectors
A car is on a driveway that is inclined 10° to the... (answered by ikleyn)
a car travels along an inclined road, in the desert, at 45 mph for 6 hours, from point a... (answered by Alan3354)
A cart weighing 50 lb is placed on a ramp inclined at 15� to the horizontal. The cart... (answered by mananth,ikleyn,amalm06)
A cart weighing 40 lb is placed on a ramp inclined at 15° to the horizontal. The cart is (answered by ikleyn)
A straight road to the top of a hill is 2500 feet long and makes an angle of 12 degrees... (answered by stanbon)