SOLUTION: Two cars pass Exit 20 on the turnpike at 8:00 A.M. One car is traveling north and the other is traveling south ata speed that is 4km/h faster than the northbound car. At 8:45 A.M.

Question 119778: Two cars pass Exit 20 on the turnpike at 8:00 A.M. One car is traveling north and the other is traveling south ata speed that is 4km/h faster than the northbound car. At 8:45 A.M. the cars are 117km apart. Find the speed of the southbound car.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
3/4X+3/4(X+4)=117
3/4X+3/4X+3=117
1.5X=117-3
1.5X=114
X=114/1.5
X=76 KM/H IS THE SPEED OF THE NORTH BOUND CAR.
76+4=80 KM/H IS THE SPEED OF THE SOUTH BOUND CAR.
PROOF
3/4^76+3/4*80=117
57+60=117
117=117

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