SOLUTION: A particular hybrid car travels approximately 318 mi on 6 gallon of gas. Find the amount of gas required for a 901-mi trip.

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Question 1197415: A particular hybrid car travels approximately 318 mi on 6 gallon of gas. Find the amount of gas required for a 901-mi trip.
Found 4 solutions by josgarithmetic, greenestamps, ikleyn, math_tutor2020:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
SIMPLE ratio, or proportion




Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


The solution method shown by the other tutor is valid; a student should understand how and why. But that method is awkward and likely confusing to many students.

I would treat this as a direct variation problem: the number of gallons of gas needed increases by the same factor as the number of miles:



ANSWER: 17 gallons
Answer by ikleyn(52782)   (Show Source): You can put this solution on YOUR website!
.
A particular hybrid car travels approximately 318 mi on 6 gallon of gas. Find the amount of gas required for a 901-mi trip.
~~~~~~~~~~~~~~ 

It is a typical problem on proportion.


After reading the problem, you write a proportion

     = ,


saying that the mileage per gallon is the same in both cases (remains unchangeable).


From the proportion, you find

    x =  = 17.


So, having 17 gallons in your gasoline tank, you may go to the road.

Solved.

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Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

mpg = miles per gallon

To get the mpg rating, divide the number of miles over the number of gallons used.

mpg = distance/gallons
mpg = 318/6
mpg = 53

This hybrid has is able to travel 53 miles for each gallon of gas.

Now we'll rearrange that formula to solve for the number of gallons
mpg = distance/gallons
gallons = distance/mpg
gallons = 901/53
gallons = 17

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