SOLUTION: A thin hoop of radius 0.50 m and a mass of 0.20 kg is released from rest and allowed to roll down an inclined plane. Calculate the rotational kinetic energy at the bottom if the an

Question 1195923: A thin hoop of radius 0.50 m and a mass of 0.20 kg is released from rest and allowed to roll down an inclined plane. Calculate the rotational kinetic energy at the bottom if the angular speed is 2.0 rad/s at that position. [Moment of inertia of thin hoop, I = MR^2, M = mass and R = radius of hoop](2 Points)

Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!



The connecting formula you need is:

   I will use w for ω (omega, normally this is used for angular speed), due to problems rendering...



Substituting for I:

  

= 

=  

=   Joule 

RELATED QUESTIONS

4. A 40.0 kg mass hung from a spring stretches the spring 87.0 cm. (a) find the spring... (answered by ikleyn)
The following are given: m1 = 10 kg, m2 = 5 kg, θ=60o, and the coefficient 
of friction  (answered by ikleyn)
A block of mass m1 is on a plane inclined at angle θ with the horizontal. It 
is... (answered by Solver92311)
A thin metal rod 8 ft long is to be bent into a circular hoop. Find the radius of this... (answered by josgarithmetic)
The moment of inertia for a point mass m at a distance R from the axis of rotation (such... (answered by ikleyn)
Two masses 6.0 kg and 9.0 kg are hung from the two ends of a cord which passes over a... (answered by ikleyn)
A mass is suspended by a spring such that it hangs at rest 0.5 m above the ground. The... (answered by ikleyn)
An elevator has a mass of 1500 kg and is carrying 10 passengers through a height of 
15... (answered by math_tutor2020)
A block is started from rest at the top of an inclined plane 6 meters long which makes 45  (answered by ikleyn)