SOLUTION: The velocity v, in meters per second, of a falling object on Earth after t seconds, ignoring the effect of air resistance, is modeled by the equation v = 9.8t. There is a different
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Question 1195267: The velocity v, in meters per second, of a falling object on Earth after t seconds, ignoring the effect of air resistance, is modeled by the equation v = 9.8t. There is a different linear relationship between time and velocity on Mars, as shown in the table below.
Time || Velocity on Mars
(second) || (meters per second)
0 || 0
4 || 14.8
8 || 29.6
If an object dropped toward the surface of Earth has a velocity of 58.8 meters per second after t seconds, what would be the velocity of the same object dropped toward the surface of Mars after t seconds, ignoring the effect of air resistance?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The velocity v, in meters per second, of a falling object on Earth after t seconds, ignoring the effect of air resistance, is modeled by the equation v = 9.8t. There is a different linear relationship between time and velocity on Mars, as shown in the table below.
Time || Velocity on Mars
(second) || (meters per second)
0 || 0
4 || 14.8
8 || 29.6
If an object dropped toward the surface of Earth has a velocity of 58.8 meters per second after t seconds, what would be the velocity of the same object dropped toward the surface of Mars after t seconds, ignoring the effect of air resistance?
----------------
v = 9.8t = 58.8
t = 6 seconds
---
On Mars:
14.8/4 = 3.7 m/sec/sec
6*3.7 = 22.2 m/sec
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