SOLUTION: Find the equation of the line that passes through (3,-5) and is perpendicular to the line that passes through (7,-5) and (-2,-4).

Question 1189584: Find the equation of the line that passes through (3,-5) and is perpendicular to the line that passes through (7,-5) and (-2,-4).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the equation of the line that passes through (3,-5) and is perpendicular to the line that passes through (7,-5) and (-2,-4).
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Step 1, find the slope of the given line = m1.
The slope of lines perpendicular is the negative inverse = -1/m1. Call it m2.
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Use y-y1 = m2*(x-x1) where (x1,y1) is the point (3,-5)
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