SOLUTION: A bus driver forgets to stop at a bus stop. Just as he passes the stop, he begins to decelerate. Five seconds later, the bus is 80m beyond the stop and has slowed to 10 m/s. a) Cal

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Question 1187328: A bus driver forgets to stop at a bus stop. Just as he passes the stop, he begins to decelerate. Five seconds later, the bus is 80m beyond the stop and has slowed to 10 m/s. a) Calculate the speed of the bus as it passed the bus stop b) What was trhe deceleration of the bus?
Answer by ikleyn(52802)   (Show Source): You can put this solution on YOUR website!
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A bus driver forgets to stop at a bus stop. Just as he passes the stop, he begins to decelerate.
Five seconds later, the bus is 80m beyond the stop and has slowed to 10 m/s.
a) Calculate the speed of the bus as it passed the bus stop
b) What was the deceleration of the bus?
~~~~~~~~~~~~~~~ 

In 5 seconds decelerating, the bus covered 80 meters.


Hence, the bus average speed vas 80/5 = 16 m/s  during this time interval.


Since the speed was changed LINEARLY as the function of time (! uniform deceleration !),
the speed of the bus before decelerating was 32 m/s.


It is the ANSWER to question (a).



Deceleration of the bus was  32 m/s : 5 seconds =  = 6   m/s^2 = 6.4 m/s^2.


It is the ANSWER to question (b).

Solved.



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