A car traveling at 45 mph overtakes a cyclist who, riding at 20 mph, had a 2-hour head start. How far from the starting point does the car overtake the cyclist?
Let distance from starting point be D
Then time taken for the car and bike to get to the meeting point = , respectively
With the car taking 2 hours less to get to meeting point, we get the following TIME equation:
4D = 9D - 360 ------ Multiplying by LCD, 180
4D - 9D = - 360
- 5D = - 360
Distance from the starting point, where the bike was overtaken, or