SOLUTION: John is on top of the building and Jack is down. If John throws ball at an angle of 60° and with initial velocity 20m/s at what height will the ball reach after 2s? Consider the m

Question 1186547: John is on top of the building and Jack is down. If John throws ball at an angle of 60° and with initial velocity 20m/s at what height will the ball reach after 2s? Consider the motion along the y direction. Show your solution. (The height of the building was not given)

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
John is on top of the building and Jack is down. If John throws ball at an angle of 60° and with initial velocity 20m/s at what height will the ball reach after 2s? Consider the motion along the y direction. Show your solution. (The height of the building was not given)
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You didn't spec the acceleration due to gravity. I'll use 10 m/sec/sec
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h(t) = -5t^2 + 20t*sin(60)
Sub 2 for t, do the arithmetic.

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