.
The distance between two cities A and B is 140 km. A car driving from A to B left at the
same time as a car driving from B to A. The cars met after one hour, then the first car reached
city B 35 minutes later than the second car reached city A. Find the speed of the car from city A to B.
~~~~~~~~~~~~~~~
Let "a" be the speed of the car A, in km/h;
let "b" be the speed of the car B, in km/h.
Then you have these two equation
a + b = 140 kilometers (1) (The cars met after one hour)
- = of an hour (2) (first car reached city B 35 minutes later than the second car reached city A)
From the first equation, express b = 140-a and substitute it into the second equation. You will get then
- =
- =
At this point, I just can to guess the solution MENTALLY : a = 60 km/h.
An alternative way is to reduce the last equation to the standard quadratic equation form and solve it formally.
ANSWER. The speed of the car A is 60 km/h.
CHECK. a) the speed of the car B is then 140-60 = 80 km/h.
b) the time equation (2) is then - = - = = = = 35 minutes.
! Correct !
Solved.