SOLUTION: Anne drove her car to Laguna from Manila. She was at 20 km when she noted that it was 9:00 AM and his speedometer indicated 50 km/h. At 9:30 AM, she saw his speedometer at 90 km/h

Question 1185380: Anne drove her car to Laguna from Manila. She was at 20 km when she noted that it was 9:00 AM and his speedometer indicated 50 km/h. At 9:30 AM, she saw his speedometer at 90 km/h and he was at 55 km. What is her acceleration (a) in km/hr/min? (b) in m/sec?
Answer by CPhill(1959) (Show Source): You can put this solution on YOUR website!
Here's how to calculate Anne's acceleration:
**(a) Acceleration in km/hr/min:**
1. **Calculate the change in velocity:**
The change in velocity (Δv) is the difference between the final speed and the initial speed:
Δv = 90 km/h - 50 km/h = 40 km/h
2. **Calculate the change in time:**
The change in time (Δt) is the difference between the final time and the initial time:
Δt = 9:30 AM - 9:00 AM = 30 minutes
3. **Calculate the acceleration:**
Acceleration (a) is the change in velocity divided by the change in time:
a = Δv / Δt
a = 40 km/h / 30 min
a = 4/3 km/hr/min or approximately 1.33 km/hr/min
**(b) Acceleration in m/s²:**
1. **Convert the change in velocity to m/s:**
Δv = 40 km/h * (1000 m/km) * (1 h/3600 s) = 100/9 m/s or approximately 11.11 m/s
2. **Convert the change in time to seconds:**
Δt = 30 min * 60 s/min = 1800 s
3. **Calculate the acceleration:**
a = Δv / Δt
a = (100/9 m/s) / 1800 s
a = 100 / (9 * 1800) m/s²
a = 1/162 m/s² or approximately 0.00617 m/s²

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