SOLUTION: An object is launched over level ground at 35 degrees above the horizontal with an initial speed of 52 m/s. What is the time of flight?

Question 1183135: An object is launched over level ground at 35 degrees above the horizontal with an initial speed of 52 m/s. What is the time of flight?
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
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An object is launched over level ground at 35 degrees above the horizontal
with an initial speed of 52 m/s. What is the time of flight?
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Calculate vertical component of the speed   = 52*sin(35°)  meters per second.


Then the time flying up to the highest point is  t =   seconds,   where g is the gravity acceleration.


The time falling dawn is the same value.


THREFORE, the total time of flight is  2t = .



All calculations are ELEMENTARY, so I leave them to you.

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You are instructed.

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