SOLUTION: A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. If each can has a weight of 5.50 N, what is the power being put out by the electric motor that driv

Question 1182900: A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor. If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor
Answer by ikleyn(52932) (Show Source): You can put this solution on YOUR website!
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A conveyor belt can lift 40 cans per second 3.40 meters up onto a casing floor.
If each can has a weight of 5.50 N, what is the power being put out by the electric motor that drives the conveyor ?
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The power  P = 40 cans * 3.40 meters up * 5.50 N = 40*3.4*5.5 = 748 joules per second = 748 watts = 0.748 kilowatts.    ANSWER

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