SOLUTION: A man runs 200 yards East and then turns around and runs 50 yards West in 35 seconds what is the man's average velocity for this trip ?
I added the yards 200 yard+50 yard = 250 ya
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Question 1182366: A man runs 200 yards East and then turns around and runs 50 yards West in 35 seconds what is the man's average velocity for this trip ?
I added the yards 200 yard+50 yard = 250 yards then divided 250/35 . Is this correct
Found 2 solutions by math_tutor2020, ikleyn:
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
Yes you are correct. The fraction you formed then becomes approximately 7.143 yards per second.
Answer by ikleyn(52928) (Show Source): You can put this solution on YOUR website!
.
This problem TEACHES you to distinct between average velocity and average speed
(which in this problem is the same as average rate).
To calculate average speed (or average rate), you should take the total traveled distance and divide it by the full spent traveled time.
But THIS PROBLEM asks about the average velocity.
Velocity is the vector, in distinct of speed and of rate.
To calculate average velocity, you should take the displacement vector and divide it by the full spent traveled time.
In this problem, the displacement is THE DIFFERENCE 200 yards MINUS 50 yards = 200 - 50 = 150 yards
and you should divide it by 35 seconds.
So, the average velocity magnitude is = = 4.286 yards per second. ANSWER
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Solved and explained.
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