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In this problem, the ball participates in two movements, at the same time.
Vertically, the ball falls with uniform acceleration g (the free fall acceleration, or gravity acceleration).
Horizontally, it moves uniformly with the constant horizontal speed.
In vertical direction, we have free fall, so
H = ,
where H is the height in meters, g = 9.81 m/s^ is the gravity acceleration, t is the time of falling.
From this formula,
t = = = 1.56 seconds (rounded).
It is the answer to the first question.
In horizontal direction, the travel is UNIFORM. THEREFORE, the horizontal traveled distance is
= 12 * 1.56 = 18.72 meters.
It is the answer to the second question.
Solved.
My solution is a standard mantra to pronounce it every time, when you solve similar problem.