SOLUTION: A plane traveling with the wind flew 1312.5 mi in 5.25 h. Against the wind, the plane required 6.25 h to fly the same distance. Find the rate of the plane in calm air and the rate

Question 1179658: A plane traveling with the wind flew 1312.5 mi in 5.25 h. Against the wind, the plane required 6.25 h to fly the same distance. Find the rate of the plane in calm air and the rate of the wind.
Found 3 solutions by mananth, MathTherapy, josgarithmetic:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
A plane traveling with the wind flew 1312.5 mi in 5.25 h. Against the wind, the plane required 6.25 h to fly the same distance.
Plane speed =x mph in still air
wind speed =y mph
against wind x-y 6.25 hours
with wind x+y 5.25 hours

Distance = same= 1312.5 miles
t=d/r
1312.5 / ( x - y )= 6.25
1120.00 /( x + 1 y) = 5.25
1.00 x 1.00 y = 179.20 ....................1
1312.5 / ( x- 1 y )= 5.25
1312.50 /( x - 1 y) = 5.25
1.00 x - 1.00 y = 250.00 ...............2
Multiply (1) by 1.00
Multiply (2) by 1.00
we get
1 x + 1 y = 179.2
1 x - 1 y = 250
2 x = 429.2
/ 2
x = 214.6 mph

Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

A plane traveling with the wind flew 1312.5 mi in 5.25 h. Against the wind, the plane required 6.25 h to fly the same distance. Find the rate of the plane in calm air and the rate of the wind.

Same MUMBO-JUMBU method by this person, and now, a WRONG answer. IGNORE it ALL!!
Use the method I pointed out earlier. It will not only be MUCH easier but you'll get the correct answer.
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
r, plane speed
w, wind speed

------ready for easy use of Elimination Method.

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