SOLUTION: Not sure how to set this one up. can you help please. Thanks solve and check t1=3 t2=2 v1 v2 = v1+8 Distance = velocity * time Given Distance = 291 Distanc

Question 117907: Not sure how to set this one up. can you help please. Thanks
solve and check

t1=3
t2=2
v1
v2 = v1+8
Distance = velocity * time
Given Distance = 291
Distance to the meeting = v1 *t1 =D1
Distance back from meeting = v2 * t2=D2
Total trip Distance = D1 + D2
291 = 3(v1) + 2(v1+8)
291 = 3v1 + 2v1 + 16
Combine like terms and solve for v1
291= 5v1 + 16
291-16 = 5v1+16-16
275 = 5v1
275/5 = v1
55 mph = v1
Now you can find v2 which is equal to v1 + 8: v2 = 55 + 8 = 63 mph
Hope that helps!
misscrt
A consultant traveled in a car for 3 hrs to attend a meeting. The return trip took only 2 hrs (different route) because his speed was 8 miles per hr faster. The total trip was 291 miles. What was the consultant's speed each way?
Answer by misscrt(37) (Show Source): You can put this solution on YOUR website!

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