SOLUTION: The length of a rectangular is 2 ft more than twice the width. The area is 60 ft^2. Find the length and width if the rectangle

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Question 1175418: The length of a rectangular is 2 ft more than twice the width. The area is 60 ft^2. Find the length and width if the rectangle
Found 3 solutions by ewatrrr, VFBundy, ikleyn:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
     .
length is 2 ft more than twice the width 'w'
     Lw = A
(2w+2)w = 60Ft^2 
2w^2 + 2w -60 = 0
 w^2 + w - 30 = 0
(w + 6)(w-5) = 0
 w = 5ft  |tossing out a negative value for length
and
 L = 12ft   

 12ft(5ft) = 60ft^2  checks.
Wish You the Best in your Studies.


Answer by VFBundy(438)   (Show Source): You can put this solution on YOUR website!
Width = w
Length = 2w + 2

w(2w + 2) = 60

2w² + 2w = 60

2w² + 2w - 60 = 0

2(w² + w - 30) = 0

w² + w - 30 = 0

(w - 5)(w + 6) = 0

w = 5 and w = -6

Since the width (w) cannot be a negative number, we can eliminate w = -6. Therefore, were are left with w = 5.

Width = w = 5
Length = 2w + 2 = 2(5) + 2 = 10 + 2 = 12
Answer by ikleyn(52756)   (Show Source): You can put this solution on YOUR website!
.
The length of a RECTANGLE is 2 ft more than twice the width.
The area is 60 ft^2. Find the length and width if the rectangle
~~~~~~~~~~~~~

        Mental solution


w*(2w+2) = 60


w*(w+1) = 30


the product of two consecutive integers is 30 -------------> hence, the numbers are 5 and 6.


ANSWER.  The width is 5 units;  the length is  2*5+2 = 12 units.

Solved.



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