SOLUTION: Car A moving at a constant velocity of 30.861 mph passes a gasoline station. Three seconds later, Car B leaves the gasoline station and accelerates at a constant rate of 6ft/ W

Question 1175326: Car A moving at a constant velocity of 30.861 mph passes a gasoline station. Three seconds later, Car B leaves the gasoline station and accelerates at a constant rate of 6ft/ What is the time of Car B to overtakes Car A.
Found 2 solutions by VFBundy, ikleyn:
Answer by VFBundy(438) (Show Source): You can put this solution on YOUR website!
The rate given here isn't complete. "6ft/"---?? Is this supposed to be 6ft/second? If it is 6 ft/second, then the answer to this question is that Car B will never overtake Car A. (Car A travels about 45ft/sec.)
Answer by ikleyn(52775) (Show Source): You can put this solution on YOUR website!
.

Dear tutor @VFBundy,

you are a great solver and a first class tutor, and work practically with no errors.

In this problem, PLEASE keep in mind that car B accelerates uniformly (!)

So, its path in "space-time" is a parabola; so, somewhen car B inevitably will overtake car A.

If and when you fix your solution, I will erase this my note.

Good luck (!)

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