Hi  



A ball is thrown from an initial height of 5 feet with an initial upward velocity of 21 ft/s. 

The ball's height h (in feet) after t seconds is given by the following.



Find all values of t for which the ball's height is 11 feet.

11 = 5+21t-16t^2

16t^2 -21t + 6 = 0                 

t = .89sec  and t = .42sec       

Wish You the Best in your Studies.





 

Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
 .


To find these values of "t", solve the equation


    5 + 21t - 16t^2 = 11   feet.


Reduce it to the standard form


    16t^2 - 21t + 6 = 0.


Use the quadratic formula.






 

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