SOLUTION: a 9:00 on saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. the bicyclist heading north is riding 4km/hour faster than the bicyclis

Question 1169955: a 9:00 on saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. the bicyclist heading north is riding 4km/hour faster than the bicyclist heading south. at 10:15 they are 40 km apart. find the two bicyclists' rates

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
In 1.25 hours, their combined speed is 40 km, so their speed per hour is 32 km/h
the speed of the slower is x and the faster x+4 km/h
that equals 32 km and the speed of the slower is 14 km/hr and the faster 18 km/hr.
in 1h15m the slower goes 17.5 km and the faster 22.5 km
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