SOLUTION: Two cyclists start from the same point and ride in opposite directions. One cyclist. One cyclist rides twice as fast as the other. In 3 h, they are 90 mi apart. Find the rate of ea

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Question 1167722: Two cyclists start from the same point and ride in opposite directions. One cyclist. One cyclist rides twice as fast as the other. In 3 h, they are 90 mi apart. Find the rate of each cyclist.
Found 2 solutions by ikleyn, dkppathak:
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.

Let r be the rate of the slower cyclist, in miles per hour (mph)


Then the rate of the faster cyclist is 2x mph.


For the total distance, you have then this equation


    3x + 3*(2x) = 90  miles,  or


    3x + 6x = 90

    9x      = 90

     x      = 90/9 = 10.


ANSWER.  The rate of the slower cyclist is 10 mph;  that of the faster cyclist is 2*10 = 20 mph.

Solved.



Answer by dkppathak(439)   (Show Source): You can put this solution on YOUR website!
Two cyclists start from the same point and ride in opposite directions. One cyclist. One cyclist rides twice as fast as the other. In 3 h, they are 90 mi apart. Find the rate of each cyclist.
let speed of first cyclist is x mile /hours and other is twice means 2x mile/hours
distance traveled by both in 3 hrs will be 3x and 6x miles
both are in opposite direction
total distance will be 3x+6x=90
9x=90
x=90/9=10 miles /hours
Answer
10 miles/hours and 20 miles /hours
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