.
Let "r" be the initial speed, in miles per hour.
Then the lower speed was (r-20) mph.
The total driving time was 10 hour from 10:00 am to 8:00 pm minus 2 hour for the rest = 8 hours.
Of them, 4 hours she drove at the rate r mph, and the remaining 8 - 4 = 4 driving hours at the lower rate (r-20) mph.
The total distance equation is
4*r + 4*(r-20) = 400
Simplify and solve
4r + 4r - 80 = 400
8r = 400 + 80 = 480
r = 480/8 = 60 mph.
ANSWER. The initial speed / (rate) was 60 mph.
Solved.
----------------
For simple Travel & Distance problems, see introductory lessons
- Travel and Distance problems
- Travel and Distance problems for two bodies moving in opposite directions
- Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.
They are written specially for you.
You will find the solutions of many similar problems there.
Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.
Become an expert in this area.