SOLUTION: Solve and verify your answer. See Example 3. (Objective 1)
A tourist can bicycle 39 miles in the same time as he can walk 9 miles. If he can ride 10 mph faster than he can walk, h
Question 1166675: Solve and verify your answer. See Example 3. (Objective 1)
A tourist can bicycle 39 miles in the same time as he can walk 9 miles. If he can ride 10 mph faster than he can walk, how much time should he allow to walk a 35-mile trail?
9 mi39 mi
Two images are displayed.
The first image depicts a person walking with an arrow underneath them pointing to the right. This image is labeled "t hr, r mph, 9 mi."
Directly below the first image, the second image depicts a person riding a bicycle with an arrow underneath pointing to the right. This arrow extends further than the first arrow. This image is labeled "t hr, (r +10) mph, 39 mi."
First, determine how fast he can walk.
1.Let r represent the rate in mph at which the tourist can walk. Write an expression in terms of r that represents the time, in hours, it takes him to walk 9 miles.
2.Write an expression in terms of r that represents the time, in hours, it takes him to bicycle 39 miles.
3.Recall that he can bicycle 39 miles in the same time that he can walk 9 miles. Use this information to write an equation that can be used to solve for r.
Once you have found r, answer the question through . Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website! t*r=9 miles
t*(r+10)=39 miles
t=9/r
t=39/(r+10)
cross multiply to get 39r=9r+90
30r=90
r=3 mph time to walk
will take 11 2/3 hours (35/3) to walk 35 miles.