SOLUTION: A salesman drives from Ajax to Barrington, a distance of 120 mi, at a steady speed. He then increases his speed by 15 mi/h to drive the 163 mi from Barrington to Collins. If the se

Question 1166481: A salesman drives from Ajax to Barrington, a distance of 120 mi, at a steady speed. He then increases his speed by 15 mi/h to drive the 163 mi from Barrington to Collins. If the second leg of his trip took 3 min more time than the first leg, how fast was he driving between Ajax and Barrington?
Answer by ikleyn(52814) (Show Source): You can put this solution on YOUR website!
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From the condition, you have this "time" equation


     -  = ,  or


     -  = .


where x is the average speed under the question, in miles per hour.


To find x, first multiply both sides by  20x*(x+15);  reduce it to the standard form quadratic equation and then solve it.

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