.
Let u be the rate of the slower car (in mph).
Then the rate of the faster car is (u+10) mph.
The total distance equation is
144 = , (1)
where represents the time of 1 hour and 36 minutes.
Since = = , you simplify equation (1)
144 = .
Next, multiply both sides by 5
720 = 8u + 8*(u+10)
90 = u + (u + 10)
90 - 10 = 2u
80 = 2u
u = 80/2 = 40.
ANSWER. The slower car rate is 40 mph; the faster car rate is 40+10 = 50 mph.
Solved.
-------------
See introductory lessons on Travel and Distance problems
- Travel and Distance problems
- Travel and Distance problems for two bodies moving in opposite directions
- Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.
They are written specially for you.
You will find the solutions of many similar problems there.
Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.
Become an expert in this area.
`````````````````
Notice that there is some defect in your condition.