SOLUTION: If 2 cars were 300 miles apart at 12 noon, and drove until they met each other at 3 pm, find the speeds of both cars. 1 car was driving at a speed of 10 mph faster then the other.

Question 1163242: If 2 cars were 300 miles apart at 12 noon, and drove until they met each other at 3 pm, find the speeds of both cars. 1 car was driving at a speed of 10 mph faster then the other.
Answer by ikleyn(52804) (Show Source): You can put this solution on YOUR website!
.


Let x be the rate of the slower car, in miles per hour;

then the rate of the faster car is (x+10) mph.


The total distance equation is then


    3x + 3*(x+10) = 300  miles   (the "3" here is "3 hours from 12 noon to 3 pm).


From the equation,


    3x + 3x + 30 = 300

    6x           = 300 - 30 = 270

     x                      = 270/6 = 45.


ANSWER.  The slower car rate was  45 mph;  the faster car  45+10 = 55 mph.

Solved.

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