Let r be his rate in still water. Then the rate downstream is (r+2) km/h; while the rate upstream is (r-2) km/h. The time to travel 5 km downstream is; The time to travel 5 kn upstream is . Now your equation becomes = . To solve it, cross multiply 5*(r+2) = 2*5*(r-2). Simplify and solve 5r + 10 = 10r - 20 10 + 20 = 10r - 5r 30 = 5r r = 30/5 = 6. ANSWER. Ed's rate in still water is 6 km/h.