SPEED TIME DISTANCE
TO r 500/r 500
BACK 2r 500/(2r) 500
Total 5
Let outbound speed be S
Then return speed = 2S
We then get the following TIME equation:
------ Reducing fractions by factoring out numerator GCF, 5
2S = 200 + 100 ------ Multiplying by LCD, 2S
Return speed or
Accept NO other ANSWER!!