SOLUTION: At noon, a passenger ship and a freighter left a port traveling in opposite directions. By midnight, the passenger ship was 3 times farther from port than was the freighter. How fa

Question 1155499: At noon, a passenger ship and a freighter left a port traveling in opposite directions. By midnight, the passenger ship was 3 times farther from port than was the freighter. How far (in mi) was the freighter from port if the distance between the ships was 88 miles?
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.


x + 3x = 88


4x     = 88


 x     = 88/4 = 22.


ANSWER.  22 miles.

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