SOLUTION: Jamie recently drove to visit her parents who live 264 miles away. On her way there her average speed was 14 miles per hour faster than on her way home (she ran into some bad weath

Question 1154223: Jamie recently drove to visit her parents who live 264 miles away. On her way there her average speed was 14 miles per hour faster than on her way home (she ran into some bad weather). If Jamie spent a total of 11 hours driving, the the two rates.
Found 2 solutions by ewatrrr, MathTherapy:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
spent a total of 11 hours driving
parents who live 264 miles away
way there her average speed was 14 miles per hour faster than on her way home
Hi,
D = rt 0r t = D/r
WRITE AS YOU READ
11 = 264/(r+14) + 264/r
Multiply each term by common Denominator..
11r(r+14)= 264r + 264(r+14)
Simplify
r(r+14) = 24r + 24(r+14) | DIVIDE EACH TERM BY 11
r^2 - 34r - 336 = 0
(r + 8) (r - 42 ) = 0 |336 factors 6*2*4*7 (8 & 42 works)
r = 42mph
Checking our Answer
264/56 + 264/42 = 11 0r
24/56 + 24/42 = 1
3/7 + 4/7 = 1 CHECKS!

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Jamie recently drove to visit her parents who live 264 miles away. On her way there her average speed was 14 miles per hour faster than on her way home (she ran into some bad weather). If Jamie spent a total of 11 hours driving, the the two rates.

Let average speed going be S
Then average return-speed = S - 14
We then get the following TIME equation:
------ Reducing fractions by factoring out GCF, 11, in numerator
24(S - 14) + 24S = S(S - 14) ------ Multiplying by LCD, S(S - 14)

0 = (S - 56)(S - 6)
S, or OR S = 6 mph (ignore)

It's as easy as A-B-C!
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