SOLUTION: a man on a long trip drove one fourth of the distance on a first day, 575 miles on the second day and 125 more than the first day on the third day. How long was the trip?

Question 1150595: a man on a long trip drove one fourth of the distance on a first day, 575 miles on the second day and 125 more than the first day on the third day. How long was the trip?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a man on a long trip drove one fourth of the distance on a first day, 575 miles on the second day and 125 more than the first day on the third day.
How long was the trip?
:
let d = the distance of the trip
d = d + 575 + (d + 125)
multiply equation by 4
4d = d + 4(575) + d + 4(125)
4d = 2d + 2300 + 500
4d - 2d = 2800
2d = 2800
d = 2800/2
d = 1400 mi
:
:
Check this
(1400) + 575 + ((1400) + 125)
350 + 575 + 350 + 125 = 1400
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