# SOLUTION: A bicycle leaves town at 16 mph at 8 am. A car leaves at 11 am, traveling in the same direction at 40 mph. How many minutes after 11 am is it when the car overtakes the bicycle?

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 Question 114860: A bicycle leaves town at 16 mph at 8 am. A car leaves at 11 am, traveling in the same direction at 40 mph. How many minutes after 11 am is it when the car overtakes the bicycle? Answer by ankor@dixie-net.com(15747)   (Show Source): You can put this solution on YOUR website!A bicycle leaves town at 16 mph at 8 am. A car leaves at 11 am, traveling in the same direction at 40 mph. How many minutes after 11 am is it when the car overtakes the bicycle? : Let t = travel time (in hrs) of the car when it overtakes the bike Then (t+3) = travel time of the bike : We know that when this happens, they will have traveled the same distance. Make a distance equation from this fact: Distance = Speed * time : Car dist = Bike dist 40t = 16(t+3) 40t = 16t + 48 40t - 16t = 48 24t = 48 t = 48/24 t = 2 hrs : To answer the question, 120 minutes after 11 : Check solution by finding the distance of each: 16(2+3) = 80 40(2) = 80 miles also