SOLUTION: carlo left their house at 9:00 am riding his bicycle at a rate of 10kph. three hours later, his brother Jaypee also left their house in a car at an average speed of 80kph heading i

Question 1145617: carlo left their house at 9:00 am riding his bicycle at a rate of 10kph. three hours later, his brother Jaypee also left their house in a car at an average speed of 80kph heading in the direction of carlo. After how many hours will jaypee overtake carlo?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
carlo left their house at 9:00 am riding his bicycle at a rate of 10kph.
three hours later, his brother Jaypee also left their house in a car at an average speed of 80kph heading in the direction of carlo.
After how many hours will jaypee overtake carlo?
:
let t = JP's travel time
C left 3 hrs earlier, therefore
(t+3) = C's travel time
:
Write a distance equation, dist = speed * time
When JP catches C, they will have traveled the same dist
80t = 10(t+3)
80t = 10t + 30
80t - 10t = 30
70t = 30
t = 30/70
t = 3/7 hrs or *60 = 27.7 minutes, for JP to catch C
:
:
Check, (3/7 = .429)
80 * .429 = 34.3 mi
10 * 3.429 = 34.3 mi
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