SOLUTION: A particle moves according to the parametric equations: y=2t^2 and x=t^3 where x and y are displacements(in meters) in x and y directions respectively and t is time in seconds.
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-> SOLUTION: A particle moves according to the parametric equations: y=2t^2 and x=t^3 where x and y are displacements(in meters) in x and y directions respectively and t is time in seconds.
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Question 1145386: A particle moves according to the parametric equations: y=2t^2 and x=t^3 where x and y are displacements(in meters) in x and y directions respectively and t is time in seconds. Determine the acceleration after 3seconds. Answer by ikleyn(52752) (Show Source):
Calculate y-component of the acceleration vector as the second derivative of "y" over t: = 4 m/s^2.
Calculate x-component of the acceleration vector as the second derivative of "x" over t and substitute t = 3 seconds: = 6t = 18 m/s^2.
Calculate the magnitude of the acceleration as | a | = = = = m/s^2.
Use your calculator to get the numerical value.
