SOLUTION: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 77 mi/h faster than the other. If the two jets are 11,208 apart after 8 hours, what

Question 1144626: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 77 mi/h faster than the other. If the two jets are 11,208 apart after 8 hours, what is the rate of each jet?

Answer by ikleyn(52795) (Show Source): You can put this solution on YOUR website!
.


8*r + 8*(r+77) = 11208  miles.     


8r + 8r + 8*77 = 11208


16r            = 11208 - 8*77


16r            = 10592


 r             = 10592/16 = 662.


ANSWER.  The slower plane rate is 662 miles per hour.  The faster plane rate is  662+77 = 739 miles per hour.

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