SOLUTION: James can jog twice as fast as he can walk. He was able to jog the first 9 miles to his grandmother’s house, but then he tired and walked the remaining 1.5 miles. If the total tr

Question 1143482: James can jog twice as fast as he can walk. He was able to jog the first 9 miles to his grandmother’s house, but then he tired and walked the remaining 1.5 miles. If the total trip took 2 hours, then what was his average jogging speed?
Found 4 solutions by ankor@dixie-net.com, ikleyn, greenestamps, josgarithmetic:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
James can jog twice as fast as he can walk.
He was able to jog the first 9 miles to his grandmother’s house, but then he tired and walked the remaining 1.5 miles.
If the total trip took 2 hours, then what was his average jogging speed?
:
let j = his jogging speed
he walks half as fast, therefore
.5j = his walking speed
:
write a time equation, time = dist/speed
jog time + walk time = 2 hrs
+ = 2
multiply by .5j
.5(9) + (1.5) = .5j(2)
4.5 + .1.5 = j
6 = j
j = 6 mph is the jogging speed
:
:
Check, find the actual time of each
9/6 = 1.5 hrs
1.5/3 = .5 hrs
-----------------
total time 2 hrs

Answer by ikleyn(52943)   (Show Source): You can put this solution on YOUR website!
.

If x miles per hour is his average jogging speed, then his average walking speed is miles per hour. The "time" equation is + = 2 hours, or, equivalently, + = 2 hours, To solve it, multiply both sides by x. You will get 9 + 3 = 2x. 12 = 2x x = 12/2 = 6 miles per hour. ANSWER. His average jogging speed is 6 miles per hour. CHECK. + = 1.5 + 0.5 = 2 hours. ! Correct !

Solved.

Answer by greenestamps(13216)   (Show Source): You can put this solution on YOUR website!

A solution using logical reasoning instead of formal algebra....

He walked for 1.5 miles at a rate half of his jogging speed.

If he had not tired and kept jogging instead, he could have covered 3 miles in the same amount of time.

So in the 2 hours it took for the whole trip he could have covered 9+3=12 miles if he had continued jogging.

That means his jogging speed is 12/2 = 6mph.
Answer by josgarithmetic(39632)   (Show Source): You can put this solution on YOUR website!

SPEED TIME DISTANCE JOG 2r 9/(2r) 9 WALK r 1.5/r 1.5 TOTAL 2

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